Bourbaki

Theorem 2

Tag 004J, permanent. Cite it as [Bourbaki, Tag 004J].

Algebra, VIII, p. 62, § 4. Semisimple Modules

Let M be an isotypical A-module of type S and (V,α)(V, \alpha ) a description of M. Denote by DD(V)\mathscr{D}_D(V) the set, ordered by inclusion, of D-linear subspaces of V, and by DA(M)\mathscr{D}_A(M) that of A-submodules of M. For every W∈W\in DD(V)\mathscr{D}_D(V), identify the A-module S⊗DWS\otimes_DW with its canonical image in S⊗DVS\otimes_DV.

a) The mapping W↦α(S⊗DW)W\mapsto \alpha (S\otimes_DW) is an isomorphism of ordered sets from DD(V)\mathscr{D}_D(V) to DA(M)\mathscr{D}_A(M).

b) The inverse isomorphism sends a submodule N of M to the linear subspace of V consisting of the elements vv such that α(s⊗v)\alpha (s\otimes v) belongs to N for every s∈Ss\in S.

For W∈DDW\in \mathscr{D}_D(V), set φ(W)=α(S⊗DW)\varphi (W) =\alpha (S\otimes_DW). For N∈DAN\in \mathscr{D}_A(M), denote by ψ(N)\psi (N) the set of elements v∈Vv\in V such that α(s⊗v)∈N\alpha (s\otimes v)\in N for every s∈Ss\in S. This defines two mappings φ:DD(V)→DA(M)\varphi :\mathscr{D}_D(V)\rightarrow \mathscr{D}_A(M) and ψ:DA(M)→DD(V)\psi :\mathscr{D}_A(M)\rightarrow \mathscr{D}_D(V). They are clearly increasing.

Let N be a submodule of M. It is isotypical of type S (VIII, p. 61, Proposition 2). Set W=ψ(N)W =\psi (N). By Proposition 3, b) of VIII, p. 62, the A-linear mappings h:S→Mh: S\rightarrow M are simply the mappings s↦α(s⊗v)s\mapsto \alpha (s\otimes v), where vv runs through V. Those with image contained in N are the mappings s↦α(s⊗w)s\mapsto \alpha (s\otimes w) where ww runs through W; their images generate N because N is isotypical of type S. We therefore have α(S⊗DW)=N\alpha (S\otimes_DW) = N, that is, φ(ψ(N))=N\varphi (\psi (N)) = N. This proves that φ∘ψ\varphi \circ \psi is the identity mapping on DA(M)\mathscr{D}_A(M). In particular, φ\varphi is surjective and ψ\psi is injective.

To finish the proof, it suffices to prove that the mapping φ\varphi is injective. Let W and W′W' be linear subspaces of V such that φ(W)=φ(W′)\varphi (W) =\varphi (W'). The vector spaces S⊗DWS\otimes_DW and S⊗DW′S\otimes_DW' coincide when viewed as linear subspaces of S⊗DVS\otimes_DV. Choose a nonzero linear form ff on the D-vector space S, and let g:S⊗DV→Vg: S\otimes_DV\rightarrow V be the group homomorphism defined by g(s⊗v)=f(s)vg(s\otimes v) =f(s)v. We have W=g(S⊗DW)=g(S⊗DW′)=W′W =g(S\otimes_DW) =g(S\otimes_DW') = W', so φ\varphi is injective.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2023, Springer Nature. Not translated.