Bourbaki

Lemma 5

Tag 00KW, permanent. Cite it as [Bourbaki, Tag 00KW].

Algebra, VIII, p. 345, § 17. Reduced Norms and Traces

For every extension K′K' of K and every element (ti)i∈I(t_i)_{i\in I} of K′I{K'}^I, we have

(48) PcrdA(K′)/K′(∑i∈Iti⊗ei)=P((ti)i∈I,X)_{A_{(K')}/K'}(\sum_{i\in I}t_i\otimes e_i)= P((t_i)_{i\in I},X).

Let φ:K[T]→K′\varphi : K[\mathbf{T}]\rightarrow K' be the unique K-algebra homomorphism that sends TiT_i to tit_i for every i∈Ii\in I; it defines on K′K' the structure of a K[TK[\mathbf{T}]-algebra. The K′K'-algebra A(K[T])(K′)A_{(K[\mathbf{T}])(K')} can be identified with A(K′)A_{(K')} (transitivity of extension of scalars), where the element 1⊗(∑Ti⊗ei)1\otimes (\sum T_i\otimes e_i) is identified with the element ∑ti⊗ei\sum t_i\otimes e_i of A(K′)A_{(K')}. We denote by φ‾:K[T][X]→K′[X]\overline{\varphi}: K[\mathbf{T}][X]\rightarrow K'[X] the K-algebra homomorphism deduced from φ\varphi. By formula (21) of III, §9, No. 3, p. 544, the characteristic polynomial of ∑ti⊗ei\sum t_i\otimes e_i with respect to the K′K'-algebra A(K′)A_{(K')} is the image by φ‾\overline{\varphi} of the characteristic polynomial of ∑Ti⊗ei\sum T_i\otimes e_i with respect to the K[TK[\mathbf{T}]-algebra A(K[T])A_{(K[\mathbf{T}])}, that is, of PnP^n. In other words, we have

(49) PcA(K′)/K′(∑i∈Iti⊗ei;X)=P((ti)i∈I,X)n_{A_{(K')}/K'}(\sum_{i\in I}t_i\otimes e_i; X)= P((t_i)_{i\in I},X)^n;

Lemma 5 then follows from Lemma 2 of VIII, p. 339.

Consider the specific case K′=KK'= K of Lemma 5. We have

(50) PcrdA/K(∑i∈Itiei;X)=P((ti)i∈I,X)_{A/K}(\sum_{i\in I}t_ie_i; X)= P((t_i)_{i\in I},X)

for every element (ti)i∈I(t_i)_{i\in I} of KIK^I. Since the polynomial P in K[T,X]K[\mathbf{T},X] is homogeneous of degree nn, it can be expanded uniquely as

P(T,X)=∑r=0n(−1)rBr(T)Xn−r(51) P(\mathbf{T},X) =\sum_{r=0}^n(-1)^rB_r(\mathbf{T}) X^{n-r} \tag{51}

where BrB_r is a homogeneous polynomial of degree rr in K[T]K[\mathbf{T}]. By formulas (46), (50), and (51), we have

br(∑i∈Itiei)=Br((ti)i∈I) b_r(\sum_{i\in I}t_ie_i)= B_r((t_i)_{i\in I})

for every element (ti)i∈I(t_i)_{i\in I} of KIK^I. Proposition 6 follows.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2023, Springer Nature. Not translated.