Theorem 1
Tag 00M1, permanent. Cite it as [Bourbaki, Tag 00M1].
Algebra, VIII, p. 367, § 19. Quaternion Algebras
Let D be an R-algebra of finite degree that is a field. Then D is isomorphic to R, C, or H.
Denote the center of D by Z, and let L be a maximal commutative subfield of D. We have by VIII, p. 265, Corollary 2; we also have because C is an algebraic closure of R. There are consequently three possible cases:
a) We have R = Z = L, so [D : Z] = 1 and D = R.
b) We have and Z = L, so [D : Z] = 1 and D = L. In this case, D is isomorphic to C.
c) We have R = Z and [L : R] = 2, so [D : R] = 4. By Proposition 4 of VIII, p. 364, the R-algebra D is isomorphic to a quaternion algebra of type , where and are nonzero elements of R. Let - Z be such that . We have . If , then there exists an such that (VI, §2, No. 6, p. 26, Theorem 3); we then have , which is absurd because D is a field. So we have . The inequality is shown analogously. There then exist elements and of such that and (loc. cit.). The algebra D is therefore isomorphic to the quaternion algebra of type (VIII, p. 362, Remark 2), that is, to H.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.