Bourbaki

Proposition 4

Tag 00LX, permanent. Cite it as [Bourbaki, Tag 00LX].

Algebra, VIII, p. 364, § 19. Quaternion Algebras

Let A be a central simple algebra of degree 4 over K. Denote the characteristic of K by p.

a) If p≠2p \neq 2, then there exist nonzero elements α\alpha and γ\gamma of K such that the algebra A is isomorphic to the quaternion algebra of type (α,0,γ)(\alpha, 0, \gamma).

b) If p=2p = 2, then there exist an element α\alpha of K and an element γ\gamma of K∗K^* such that the algebra A is isomorphic to the quaternion algebra of type (α,1,γ)(\alpha, 1, \gamma).

By Wedderburn's theorem (VIII, p. 120, Theorem 1), there exist an integer r≥1r \geq 1 and a field D with center K such that A is isomorphic to Mr(D)\mathbf{M}_r(D). We then have r2[D:K]=[A:K]=4r^2[D : K] = [A : K] = 4. If r=2r = 2, then A is isomorphic to M2(K)\mathbf{M}_2(K), and Proposition 4 follows from the example of VIII, p. 362. Otherwise, we have r=1r = 1, and A is a field with center K. It then has a maximal commutative subfield E that is a separable extension of K; since A has degree 4 over K, the extension E has degree 2 over K (VIII, p. 265, Corollary 2). It is therefore quadratic (III, §2, No. 3, p. 439). Let ss be the conjugation of E (III, §2, No. 3, p. 440). By the Skolem–Noether theorem (VIII, p. 256, Corollary 1), there exists an invertible element jj of A such that we have s(x)=jxj−1s(x) =jxj^{-1} for every xx in E. The field E is separable over K, so we have s≠s\not= IdE_E, so that j∉Ej \notin E. Since A is a vector space of dimension 4 over K, it is a left vector space of dimension 2 over E, so we have A=E⊕EjA = E\oplus Ej. We have s2=s^2= IdE_E, so the element j2j^2 of A belongs to the center of A; hence there exists an element γ\gamma of K∗K^* such that j2=γj^2=\gamma.

When p≠2p\not= 2, there exist an element ii of E and an element α∈K∗\alpha \in K^* such that E=K(i)E = K(i) and i2=αi^2=\alpha (V, §11, No. 9, p. 93, Example 3); in this case, A is isomorphic to the quaternion algebra of type (α,0,γ)(\alpha ,0, \gamma ). When p=2p= 2, there exist an element ii of E and an element α\alpha of K such that E=K(i)E = K(i) and i2=i+αi^2=i+\alpha (V, §11, No. 9, p. 93, Example 2), so that A is isomorphic to the quaternion algebra of type (α,1,γ)(\alpha ,1, \gamma ).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Cites

Transcribed from the printed edition, 2023, Springer Nature. Not translated.