Proposition 4
Tag 00LX, permanent. Cite it as [Bourbaki, Tag 00LX].
Algebra, VIII, p. 364, § 19. Quaternion Algebras
Let A be a central simple algebra of degree 4 over K. Denote the characteristic of K by p.
a) If , then there exist nonzero elements and of K such that the algebra A is isomorphic to the quaternion algebra of type .
b) If , then there exist an element of K and an element of such that the algebra A is isomorphic to the quaternion algebra of type .
By Wedderburn's theorem (VIII, p. 120, Theorem 1), there exist an integer and a field D with center K such that A is isomorphic to . We then have . If , then A is isomorphic to , and Proposition 4 follows from the example of VIII, p. 362. Otherwise, we have , and A is a field with center K. It then has a maximal commutative subfield E that is a separable extension of K; since A has degree 4 over K, the extension E has degree 2 over K (VIII, p. 265, Corollary 2). It is therefore quadratic (III, §2, No. 3, p. 439). Let be the conjugation of E (III, §2, No. 3, p. 440). By the Skolem–Noether theorem (VIII, p. 256, Corollary 1), there exists an invertible element of A such that we have for every in E. The field E is separable over K, so we have Id, so that . Since A is a vector space of dimension 4 over K, it is a left vector space of dimension 2 over E, so we have . We have Id, so the element of A belongs to the center of A; hence there exists an element of such that .
When , there exist an element of E and an element such that and (V, §11, No. 9, p. 93, Example 3); in this case, A is isomorphic to the quaternion algebra of type . When , there exist an element of E and an element of K such that and (V, §11, No. 9, p. 93, Example 2), so that A is isomorphic to the quaternion algebra of type .
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.