Bourbaki

Remark 2

Tag 00MH, permanent. Cite it as [Bourbaki, Tag 00MH].

Algebra, VIII, p. 377, § 20. Linear Representations of Algebras

Let E be an A-module, and let E′E' be a submodule of E. By the corollary of Theorem 5 of II, §7, No. 5, p. 299, we have ΘE′(A)⊂ΘE(A)\Theta_{E'}(A)\subset \Theta_E(A) and ΘE/E′(A)⊂ΘE(A)\Theta_{E/E'}(A)\subset \Theta_E(A).

Let γE\gamma_E be the unique K-linear mapping from E⊗KE∗E\otimes_KE^* to A∗A^* that sends x⊗x∗x\otimes x^* to cE(x,x∗)c_E(x, x^*). It is (A(A, A)-bilinear, and its image is ΘE(A)\Theta_E(A). We deduce from it A-linear mappings cE′:E→c'_E: E\rightarrow HomA(E∗,A∗)_A(E^*,A^*) and cE′′:E∗→c''_E: E^*\rightarrow HomA(E,A∗)_A(E,A^*) such that

cE′(x)(x∗)=cE(x,x∗)=cE′′(x∗)(x) c'_E(x)(x^*) =c_E(x, x^*) =c''_E(x^*)(x)

Denote by θE\theta_E the K-linear mapping θE:E⊗E∗→\theta_E: E\otimes E^*\rightarrow EndK(E)_K(E) characterized by the relation

θE(x⊗x∗)(y)=⟨x∗,y⟩x \theta_E(x\otimes x^*)(y) =\langle x^*, y\rangle x

for x,y∈Ex, y\in E and x∗∈E∗x^*\in E^*. Its image is the set EndKf(E)^f_K(E) of endomorphisms of E of finite rank (VIII, p. 463). By the definition of the trace (loc. cit.), we have

Tr(θE(x⊗x∗)\theta_E(x\otimes x^*)) =⟨x∗,x⟩=\langle x^*, x\rangle

for x∈Ex\in E and x∗∈E∗x^*\in E^*; we therefore have

⟨γE(x⊗x∗),a⟩=⟨x∗,ax⟩=\langle \gamma_E(x\otimes x^*), a\rangle =\langle x^*, ax\rangle = Tr(θE(ax⊗x∗)\theta_E(ax\otimes x^*)) == Tr(θE(x⊗x∗)a\theta_E(x\otimes x^*)a).

This gives the relation

⟨γE(h),a⟩=\langle \gamma_E(h), a\rangle = Tr(θE(h)∘aE\theta_E(h)\circ a_E)

for a∈Aa\in A and h∈E⊗KE∗h\in E\otimes_KE^*. This proves that ΘE(A)\Theta_E(A) is the set of linear forms a↦a\mapsto Tr(u∘aEu\circ a_E) on A, where uu runs through EndKf(E)^f_K(E).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Cites

  • corollary of Theorem 5 of II, §7, No. 5, p. 299 not in this corpus
  • VIII, p. 463
Transcribed from the printed edition, 2023, Springer Nature. Not translated.