The homomorphism π1(D(G))→π1(G) corresponding to the inclusion of D(G) into G induces an isomorphism from π1(D(G)) to the torsion subgroup of π1(G).
Indeed, T∩D(G) is a maximal torus of D(G) (§2, no. 3, Prop. 1c)); from the exact sequence
0⟶Γ(T∩D(G))⟶Γ(T)⟶Γ(T/(T∩D(G)))⟶0
and Proposition 11, we obtain an exact sequence
0⟶π1(D(G))⟶π1(G)⟶Γ(T/(T∩D(G)))⟶0
hence the corollary, since π1(D(G)) is finite and Γ(T/(T∩D(G))) is free.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.