Bourbaki

Proposition 10

Tag 04GX, permanent. Cite it as [Bourbaki, Tag 04GX].

Commutative Algebra, chapter III, § 3. m-adic topologies on Noetherian rings

Let A,BA, B be two Zariski rings, A^,B^\hat{A}, \hat{B} their completions, f:A→Bf : A \to B a continuous ring homomorphism and f^:A^→B^\hat{f} : \hat{A} \to \hat{B} the homomorphism obtained from ff by passing to the completions; if f^\hat{f} is bijective, the AA-module BB is faithfully flat.

As AA and BB are Hausdorff, the hypothesis that f^\hat{f} is bijective implies first that ff is injective. Identifying (algebraically) AA with f(A)f(A) by means off and A^\hat{A} with B^\hat{B} by means of f^\hat{f}, we then obtain the inclusions A⊂B⊂A^=8A \subset B \subset \hat{A} = \mathbf{8}; we know that A^\hat{A} is a faithfully flat AA-module and a faithfully flat BB-module (Proposition 9); we conclude that BB is a faithfully flat AA-module (Chapter I, § 3, no. 4, Remark 2).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.