Theorem 1
Tag 04S1, permanent. Cite it as [Bourbaki, Tag 04S1].
Commutative Algebra, chapter VI, § 1. Valuation rings
Let K be a field and V a subring of K. The following conditions are equivalent: (a) V is a maximal element of the set of local subrings of K, this set being ordered by the relation "B dominates A" between A and B. (b) There exists an algebraically closed field L and a homomorphism h from V to L which is maximal in the set of homomorphisms from subrings of K to L, ordered by the relation "g is an extension off" between f and g. (c) If , then . (d) The field of fractions of V is K and the set of principal ideals of V is totally ordered by the relation of inclusion. (e) The field of fractions of V is K and the set of ideals of V is totally ordered by the relation of inclusion.
We shall show the theorem by proving the following implications
Suppose that (a) holds. Then is a local ring. Let be an algebraic closure of the residue field and the canonical homomorphism from to . Let be a subring of containing and a homomorphism from to extending . If is the kernel of , then ; hence (no. 1, Example 2) dominates , which implies and . Thus (b) holds.
Suppose (b) holds. Let be an algebraically closed field and a homomorphism from to ; suppose that is maximal in the set of homomorphisms from subrings of to ; let be the kernel of . The elements of being invertible in , can be extended to a homomorphism from to (Chapter II, § 2, no. 1, Proposition 1); hence , which shows that is a local ring and that is its maximal ideal. Let be a non-zero element of ; we must show that one at least of the elements belongs to , that is, by virtue of the maximal character of , that can be extended to or . If is integral over , this follows from Chapter V, § 2, no. 1, Corollary 4 to Theorem 1. If is not integral over , we shall use the following lemma:
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Cited by
- § 1. Valuation rings
- Definition 2, § 1
- Theorem 2, § 1
- Corollary 3, § 1
- Lemma 1, § 3
- Proposition 3, § 3
- Corollary, § 4