Bourbaki

Theorem 1

Tag 04S1, permanent. Cite it as [Bourbaki, Tag 04S1].

Commutative Algebra, chapter VI, § 1. Valuation rings

Let K be a field and V a subring of K. The following conditions are equivalent: (a) V is a maximal element of the set of local subrings of K, this set being ordered by the relation "B dominates A" between A and B. (b) There exists an algebraically closed field L and a homomorphism h from V to L which is maximal in the set of homomorphisms from subrings of K to L, ordered by the relation "g is an extension off" between f and g. (c) If x∈K−Vx \in K - V, then x−1∈Vx^{-1} \in V. (d) The field of fractions of V is K and the set of principal ideals of V is totally ordered by the relation of inclusion. (e) The field of fractions of V is K and the set of ideals of V is totally ordered by the relation of inclusion.

We shall show the theorem by proving the following implications

(a)⇒(b)⇒(c)⇒(d)⇒(e)⇒(a).(a) \Rightarrow (b) \Rightarrow (c) \Rightarrow (d) \Rightarrow (e) \Rightarrow (a).

Suppose that (a) holds. Then VV is a local ring. Let LL be an algebraic closure of the residue field κ(V)\kappa(V) and hh the canonical homomorphism from VV to LL. Let V′V' be a subring of KK containing VV and h′h' a homomorphism from V′V' to LL extending hh. If p′p' is the kernel of h′h', then p′∩V=m(V)p' \cap V = m(V); hence (no. 1, Example 2) Vp′′V'_{p'} dominates VV, which implies Vp′′=VV'_{p'} = V and V′=VV' = V. Thus (b) holds.

Suppose (b) holds. Let LL be an algebraically closed field and hh a homomorphism from VV to LL; suppose that hh is maximal in the set of homomorphisms from subrings of KK to LL; let pp be the kernel of hh. The elements of h(V−p)h(V - p) being invertible in LL, hh can be extended to a homomorphism from VpV_p to LL (Chapter II, § 2, no. 1, Proposition 1); hence V=VpV = V_p, which shows that VV is a local ring and that pp is its maximal ideal. Let xx be a non-zero element of KK; we must show that one at least of the elements x,x−1x, x^{-1} belongs to VV, that is, by virtue of the maximal character of hh, that hh can be extended to V[x]V[x] or V[x−1]V[x^{-1}]. If xx is integral over VV, this follows from Chapter V, § 2, no. 1, Corollary 4 to Theorem 1. If xx is not integral over VV, we shall use the following lemma:

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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