Bourbaki

Proposition 1

Tag 04VN, permanent. Cite it as [Bourbaki, Tag 04VN].

Commutative Algebra, chapter VI, § 7. Approximation theorem

Let KK be a field, (Ai)1≤i≤n(\mathbf{A}_i)_{1 \leq i \leq n} ajinitefamily of valuation rings of KK and B=⋂i=1nAiB = \bigcap_{i=1}^n \mathbf{A}_i. We write pi=B∩m(Ai)p_i = B \cap m(\mathbf{A}_i). Then Ai=BpiA_i = B_{p_i} for all ii and the jield of ructions of BB is KK.

Clearly Bpi⊂AiB_{p_i} \subset A_i. To prove the converse inclusion we need the following lemma:

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Cites

Nothing.

Transcribed from the printed volume. Not translated.