Bourbaki

Definition 4

Tag 05IV, permanent. Cite it as [Bourbaki, Tag 05IV].

Algebra, chapter I, § 9. Fields

The field of fractions of the ring Z\mathbf{Z} of rational integers is called the field of rational numbers and is denoted by Q\mathbf{Q}. The elements of Q\mathbf{Q} are called rational numbers.

Every rational number is thus of the form a/ba/b where aa and bb are rational integers with b≠0b \neq 0 (and we may even take b>0b > 0 as the relation

a/b=(−a)/(−b) a/b = (-a)/(-b)

proves). Q+\mathbf{Q}_+ is used to denote the set of rational numbers of the form a/ba/b with a∈Na \in \mathbf{N} and b∈N∗b \in \mathbf{N}^*.

We have the relations:

(1)

Q++Q+=Q+ \mathbf{Q}_+ + \mathbf{Q}_+ = \mathbf{Q}_+
(2)
Q+⋅Q+=Q+ \mathbf{Q}_+ \cdot \mathbf{Q}_+ = \mathbf{Q}_+
(3)
Q+∩(−Q+)={0} \mathbf{Q}_+ \cap (-\mathbf{Q}_+) = \{0\}
(4)
Q+∪(−Q+)=Q \mathbf{Q}_+ \cup (-\mathbf{Q}_+) = \mathbf{Q}
(5)
Q+∩Z=N \mathbf{Q}_+ \cap \mathbf{Z} = \mathbf{N}

The first two follow from the formulae a/b+a′/b′=(ab′+a′b)/bb′a/b + a'/b' = (ab' + a'b)/bb', (a/b)(a′/b′)=aa′/bb′(a/b)(a'/b') = aa'/bb', 0∈Q+0 \in \mathbf{Q}_+, 1∈Q+1 \in \mathbf{Q}_+ and the fact that N\mathbf{N} is stable under addition and multiplication and N∗\mathbf{N}^* under multiplication. Obviously 0∈Q+0 \in \mathbf{Q}_+, whence 0∈(−Q+)0 \in (-\mathbf{Q}_+); let xx be in Q+∩(−Q+)\mathbf{Q}_+ \cap (-\mathbf{Q}_+); then there exist positive integers a,b,a′,b′a, b, a', b' with b≠0, b′≠0b \neq 0,\ b' \neq 0 and x=a/b=−a′/b′x = a/b = -a'/b'; then ab′+ba′=0ab' + ba' = 0, whence ab′=0ab' = 0 (for ab′≥0ab' \geq 0 and ba′≥0ba' \geq 0) and therefore a=0a = 0 since b′≠0b' \neq 0; in other words, x=0x = 0. Finally, obviously N⊂Z\mathbf{N} \subset \mathbf{Z} and N⊂Q+\mathbf{N} \subset \mathbf{Q}_+. Conversely, if xx belongs to Z∩Q+\mathbf{Z} \cap \mathbf{Q}_+, it is a rational integer; there exist two rational integers aa and bb with a≥0, b>0a \geq 0,\ b > 0 and x=a/bx = a/b, whence a=bxa = bx; if x∉Nx \notin \mathbf{N}, then −x>0-x > 0, whence −a=b(−x)>0-a = b(-x) > 0 and consequently a<0a < 0 contrary to the hypothesis.

Given two rational numbers xx and yy, we write x≤yx \leq y if y−x∈Q+y - x \in \mathbf{Q}_+. It is easily deduced from formulae (1), (3) and (4) that x≤yx \leq y is a total ordering on

Q, from (5) that this relation induces the usual order relation on Z. Finally, from (1) it follows that the relations x≤yx \leq y and x′≤y′x' \leq y' imply x+x′≤y+y′x + x' \leq y + y' and from (2) that the relation x≤yx \leq y implies xz≤yzxz \leq yz for all z≥0z \geq 0 and xz≥yzxz \geq yz for z≤0z \leq 0 (cf. VI, § 2, no. 1).

Let xx be a rational number. xx is said to be positive if x≥0x \geq 0, strictly positive if x>0x > 0, negative if x≤0x \leq 0 and strictly negative if x<0x < 0.† The set of positive rational numbers is Q+\mathbf{Q}_+ and that of negative numbers is −Q+-\mathbf{Q}_+. If Q∗\mathbf{Q}^* denotes the set of non-zero rational numbers, the set Q+∗\mathbf{Q}_+^* of strictly positive numbers is equal to Q∗∩Q+\mathbf{Q}^* \cap \mathbf{Q}_+ and −Q+∗-\mathbf{Q}_+^* is the set of strictly negative numbers.

The sets Q+∗\mathbf{Q}_+^* and {1,−1}\{1, -1\} are subgroups of the multiplicative group Q∗\mathbf{Q}^*. Every rational number x≠0x \neq 0 can be expressed in one and only one way in the form 1.y,(−1).y1.y, (-1).y, where y>0y > 0; hence the multiplicative group Q∗\mathbf{Q}^* is the product of the subgroups Q+∗\mathbf{Q}_+^* and {1,−1}\{1, -1\}, the component of xx in Q+∗\mathbf{Q}_+^* is called the absolute value of xx and is denoted by ∣x∣|x|; the component of xx in {−1,1}\{-1, 1\} (equal to 1 if x>0x > 0, to −1-1 if x<0x < 0) is called the sign of xx and denoted by sgn⁡ x\operatorname{sgn}\, x.

Usually these two functions are extended to the whole of Q\mathbf{Q} by setting ∣0∣=0|0| = 0 and sgn⁡ 0=0\operatorname{sgn}\, 0 = 0.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 1998, Springer. Not translated.