Lemma 1
Tag 05RK, permanent. Cite it as [Bourbaki, Tag 05RK].
Algebra, chapter II, § 7. Vector spaces
Let (a_i)_{i \in I} be a free family of elements of E; if b \in E does not belong to the subspace F generated by (a_i), the subset of E consisting of the a_i and b is free.
Suppose that there were a relation with and for all , the family having finite support; if , it would follow that and hence contrary to the hypothesis; hence and the relation becomes , which implies for all by hypothesis; whence the lemma.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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