*Let E,F be two vector spaces over a field K. For every linear mapping u of E into F, the dimension of the subspace u(E) of F is called the rank of u and denoted by rg(u).
If N=Ker(u), E/N is isomorphic to u(E), whence the relation
rg(u)=codimE(Ker(u))
and therefore
rg(u)+dim(Ker(u))=dimE.
Moreover, by formula (3)
rg(u)+dim(Coker(u))=dimF.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.