Bourbaki

Remark

Tag 05TH, permanent. Cite it as [Bourbaki, Tag 05TH].

Algebra, chapter II, § 7. Vector spaces

Let EE be a module over any commutative ring AA. If xx is a non-free element of EE, every element of the submodule AxAx is non-free. On the other hand, if AA contains divisors of 0, the sum of two non-free elements of EE may be free; for example, in Z/6Z\mathbf{Z}/6\mathbf{Z} considered as a module over itself, 3 and 4 are not free, but 3+4=13 + 4 = 1 is free.

Proposition 23 leads to the following definition:

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 1998, Springer. Not translated.