Bourbaki

Proposition 6

Tag 05VD, permanent. Cite it as [Bourbaki, Tag 05VD].

Algebra, chapter II, § 8. Restriction of the field ofscalars in vector spaces

(i) Given a system of homogeneous linear equations

(2)

∑i∈Iαμiξi=0(μ∈M) \sum_{i \in I} \alpha_{\mu i} \xi_i = 0 \quad (\mu \in M)
whose coefficients αμi\alpha_{\mu i} belong to K', every solution (ξi)(\xi_i) of this system consisting of elements of K is a linear combination with coefficients in K of solutions (ξi′)(\xi'_i) of (2) consisting of elements of K'.

(ii) Given a system of linear equations

∑i∈Iαμiξi=βμ(μ∈M) \sum_{i \in I} \alpha_{\mu i} \xi_i = \beta_\mu \quad (\mu \in M)

whose coefficients αμi\alpha_{\mu i} and right hand sides βμ\beta_\mu belong to K′K', if there exists a solution to the system consisting of elements of KK, there also exists a solution consisting of elements of K′K'.

(i) For every set S, let the right vector K-space Kd(S)K_d^{(S)} be given the K′K'-structure Kd′(S)K_{d'}^{(S)}. Let ff be the K-linear mapping of Kd(I)K_d^{(I)} into Kd(M)K_d^{(M)} mapping every vector (ξi)i∈I(\xi_i)_{i \in I} to the vector (ζμ)μ∈M(\zeta_\mu)_{\mu \in M} defined by ζμ=∑i∈Iαμiξi\zeta_\mu = \sum_{i \in I} \alpha_{\mu i} \xi_i for all μ∈M\mu \in M. Clearly ff is rational over K′K'; its kernel V, which is the set of solutions in K of the system (2), is a subspace of Kd(I)K_d^{(I)} rational over K′K' (no. 3, Corollary 2 to Proposition 3) and hence generated by the solutions of (2) in K′K'.

(ii) We consider K as a left vector K′K'-space; there exists a K′K'-linear projector pp of K onto its vector subspace Ks′K'_s (§ 7, no. 3, Proposition 4); if (ξi)(\xi_i) is a solution of (3) in K, then ∑i∈Iαμip(ξi)=p(∑i∈Iαμiξi)=p(βμ)=βμ\sum_{i \in I} \alpha_{\mu i} p(\xi_i) = p \left( \sum_{i \in I} \alpha_{\mu i} \xi_i \right) = p(\beta_\mu) = \beta_\mu, which proves that (p(ξi))(p(\xi_i)) is a solution of (3) in K′K'.

A ring K is called (left) faithfully flat over a subring K′K' if Proposition 6 holds for K and K′K'; we shall study this notion in detail later (Commutative Algebra, I, § 3).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed edition, 1998, Springer. Not translated.