Let f:V1→V2 be a K-linear mapping rational over K′. For every vector sub-K-space W1 of V1 (resp. W2 of V2) rational over K′, f(W1) (resp. f−1(W2)) is a vector sub-K-space of V2 (resp. V1) rational over K′.
In the notation of Proposition 3, for every vector sub-K′-space W1′ of V1′, f(K)′(W1′⊗K′K)=f′(W1′)⊗K′K; whence the assertion relating to W1 (no. 2, Proposition 2). On the other hand, let W2′ be a vector sub-K′-space of V2′ and let g′ be the canonical K′-linear mapping V2′→V2′/W2′; then f′(W2′)=Ker(g′∘f′); hence, by Corollary 1,
f(K)′−1(W2′⊗K′K)=f′−1(W2′)⊗K′K, whence the assertion relating to
W2.
Let V1,V2 be two right vector K-spaces with K′-structures V1′,V2′ respectively. It is immediate that V1′×V2′ is a K′-structure on V1×V2, called the product of the K′-structures V1′ and V2′.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.