With the hypotheses on Δ and A of Proposition 6, let u:M→N be a graded homomorphism of graded right A-modules, where N is assumed to be finitely generated. If the homomorphism
u⊗1:M⊗A(A/J0)→N⊗A(A/J0)
is surjective, then u is surjective.
u(M) is a graded submodule of N and the (A/J0)-module
(N/u(M))⊗A(A/J0)
is isomorphic to (N⊗A(A/J0))/Im(u⊗1) (§ 3, no. 6, Proposition 6). The hypothesis therefore implies (N/u(M))⊗A(A/J0)=0 and hence N=u(M) by Corollary 1.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.