*Let A be a commutative ring, M an A-module, B the A-algebra T(M) (resp. S(M), resp. Λ(M)) and E a (B,B)-bimodule. Let d0:A→E be a derivation of the ring A into the A-module E and d1:M→E an additive group homomorphism such that, for all a∈A and all x∈M,
(29)d1(ax)=ad1(x)+d0(a)⋅x,
and further, when B=S(M),
(30)x⋅d1(y)+d1(x)⋅y=y⋅d1(x)+d1(y)⋅x
for all x,y in M, and, when B=⋀(M),
(31)x⋅d1(x)+d1(x)⋅x=0
for all x∈M. Then there exists one and only one derivation d of B (considered as a Z-algebra) into the (B,B)-bimodule E such that d∣A=d0 and d∣M=d1.
We take on the Z-module B⊕E the associative Z-algebra structure defined by
(b,t)(b′,t′)=(bb′,bt′+tb′)
which has (1,0) as unit element (no. 8, Proposition 13). Under the canonical injection t↦(0,t), E is identified with a two-sided ideal of B⊕E such that E2={0}. On the other hand, the mapping h0:B⊕E defined by h0(a)=(a,d0(a)) is a unital ring homomorphism (no. 8, Proposition 12); under this mapping, B⊕E then becomes an A-algebra. Moreover, if, for all x∈M, we write h1(x)=(x,d1(x)), it follows from the definition of h0 and (29) that h1(ax)=h0(a)h1(x); in other words h1 is an A-linear mapping of M into B⊕E. Then there exists one and only one A-algebra homomorphism, h:B→B⊕E such that h∣M=h1 (and necessarily h∣A=h0): for, if B=T(M), this follows from §5, no. 1, Proposition 1; if B=S(M), condition (30) shows that h(x)h(y)=h(y)h(x) for all x,y in M and the conclusion follows from §6, no. 1, Proposition 2; finally if B=⋀(M), condition (31) shows that (h(x))2=0 for all x∈M, since x∧x=0 and the conclusion follows from §7, no. 1, Proposition 1. The homomorphism h is such that the composition p∘h:B→B with the augmentation ρ:B⊕E→B is the identity lB, for p∘h and lB coincide by definition for the elements of A and those of M and the set of these elements is a generating system of B. We can therefore write h(b)=(b,d(b)) for all b∈B and the mapping b↦d(b) of B into E is a derivation with the required properties, by virtue of Proposition 12 of no. 8.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.