Bourbaki

Proposition 1

Tag 070Z, permanent. Cite it as [Bourbaki, Tag 070Z].

Algebra, chapter VII, § 1. Principal ideal domains

Let KK be the field of fractions of a principal ideal domain AA, and let (xi)i∈I(x_i)_{i \in I} be a family of elements of KK having a common denominator b∈K∗b \in K^* (in other words bxi∈Abx_i \in A for all ii). Then:

a) The family (xi)(x_i) has a gcd in KK. b) Every gcd of (xi)(x_i) can be expressed in the form d=∑aixid = \sum a_i x_i, where the aia_i are elements of AA, all but finitely many of which are zero.

Indeed the ideal ∑Abx\sum Abx, of AA is principal, and so of the form Ad′Ad'. Put d′=bd (d∈K)d' = bd \ (d \in K). From the relation d′=∑aibxid' = \sum a_i b x_i, we deduce d=∑aixid = \sum a_i x_i, where ai∈Aa_i \in A. Hence every common divisor of the xix_i divides dd. On the other hand, since bdbd is a common divisor of the bxbx, by construction, it follows that dd is a common divisor of the xix_i.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Transcribed from the printed edition, 2003, Springer. Not translated.