Let ν be the product premeasure of λ and μ; for every function f∈F+(S) and every function g∈F+(T),
ν∙(f⊗g)=λ∙(f)μ∙(g).
The premeasure ν is the only premeasure on S×T that satisfies (4).
As K (resp. L) runs over the set of compact subsets of S (resp. of T), we have
ν∙(f⊗g)=K,LsupνK×L∙((f⊗g)K×L)=K,Lsup(λK⊗μL)∙(fK⊗gL)=K,LsupλK∙(fK)⋅μL∙(gL)=(KsupλK∙(fK))(LsupμL∙(gL))=λ∙(f)μ∙(g)
by Prop. 8 of Ch. V, §8, No. 3.
Let η be a second premeasure on S×T satisfying (4), and let K and L be compact subsets of S and T respectively, f and g elements of F+(K) and F+(L) respectively. One has the relation (f⊗g)0=f0⊗g0 between the extensions by 0, therefore (§1, No. 2, Prop. 2)
ηK×L∙(f⊗g)=η∙((f⊗g)0)=η∙(f0⊗g0)=λ∙(f0)μ∙(g0)=λK∙(f)μL∙(g).
In particular, if one takes f∈K+(K), g∈K+(L), one sees that ηK×L has the characteristic property of the product measure λK⊗μL (Ch. III, §4, No. 1, Th. 1). Therefore ηK×L=νK×L; since every compact subset of S×T is contained in a set of the form K×L, the transitivity of induced measures implies that η=ν.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.