Proposition 24
Tag 0A8N, permanent. Cite it as [Bourbaki, Tag 0A8N].
Lie Groups and Lie Algebras, chapter III, § 1. Lie groups
Let G be a Lie group germ, X a manifold of class C^r and (X_i)_{i \in I} a locally finite open covering of X. For all i \in I, let be a law chunk of left operation of class C^r of G on X_i. Suppose that the underlying topological space of X is normal and that, for all (i, j) \in I \times I and all x \in X_i \cap X_j, and coincide on a neighbourhood of (e, x). There exists a law chunk of left operation of class C^r of G on X such that, for all i \in I and all x \in X_i, and coincide on a neighbourhood of (e, x).
For all (i, j) \in I \times I and all x \in X_i \cap X_j, choose an open neighbourhood V_{ij}(x) of x in X_i \cap X_j such that and are defined and equal on a neighbourhood of {e} \times V_{ij}(x) in G \times X. For all x \in X choose an open neighbourhood V(x) of x in X such that conditions (a) and (b) of Lemma 3 are fulfilled. Let I_x be the set of i \in I such that x \in X_i. This is a finite set. Let U_x be the set of (g, y) \in G \times V(x) such that the for i \in I_x are defined and coincide on a neighbourhood of (g, y). Then U_x is open and (e, x) \in U_x. The for i \in I_x all have the same restriction to U_x. Let x, y be in X. If U_x and U_y meet, V(x) and V(y) meet and hence there exists i \in I such that
Then i \in I_x, i \in I_y, and hence
The therefore define a mapping of into X and U is an open neighbourhood of {e} \times X in G \times X. Clearly is of class C^r and for all x \in X. For all i \in I and all x \in X_i, coincides with and hence with in a neighbourhood of (e, x) and hence satisfies condition (iii) of Definition 6.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.