Bourbaki

Theorem 2

Tag 0ASS, permanent. Cite it as [Bourbaki, Tag 0ASS].

Lie Groups and Lie Algebras, chapter V, § 5. Invariants in the symmetric algebra

Retain the assumptions and notation of Theorem 1.

(i) There exists a graded vector subspace of S forming a complement to R+SR_+ S in S and stable under G.

(ii) Let U be such a complement. The canonical homomorphism from U⊗KRU \otimes_K R to S is an isomorphism of G-modules, and the representation of G in U (resp. S) is isomorphic to the regular representation of G on K (resp. R).

Indeed, for any integer n≥0n \geq 0, the K-vector spaces SnS_n and (R+S)∩Sn(R_+ S) \cap S_n are stable under G, and it follows from Maschke’s theorem (Appendix, Prop. 2) that there exists a G-stable complement UnU_n of (R+S)∩Sn(R_+ S) \cap S_n in SnS_n. Then ∑n≥0Un\sum_{n \geq 0} U_n is a G-stable complement of R+SR_+ S in S, hence (i).

Let U be a graded vector subspace of S forming a complement of R+SR_+ S in S and stable under G. By Remark 1, every basis of the K-vector space U is also a basis of the R-module S, and consequently is a basis of the field of fractions N of S over the field of fractions L of R. Thus, the L-vector space N can be identified with U⊗KLU \otimes_K L. Since U is stable under G, this identification is compatible with the action of G. The group algebra L[G]L[G] of G over L can be identified with the algebra K[G]⊗KLK[G] \otimes_K L. The Galois extension N of L admits a normal basis (Algebra, Chap. V, § 10, no. 9, Th. 6), which can be interpreted as saying that N, considered as an L[G]L[G]-module, is isomorphic to the module of the regular representation of G over L. Since U is finite dimensional over K, it follows from the Appendix, Prop. 1, that the K[G]K[G]-module U is isomorphic to the regular representation of G over K. Our assertions follow immediately from this.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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