a) Let (Xi)i∈I be a family of locally connected spaces such that Xi is connected for all but a finite number of indices i∈I. Then the product space X=∏i∈IXi is locally connected.
b) Conversely, if the product of a family (Xi) of non-empty topological spaces is locally connected, then each Xi is locally connected, and Xi is connected for all but a finite number of indices.
a) Let J be the finite subset of I such that Xi is not connected if and only if i∈J. Let
U=i∈I∏Ui be an elementary set containing a point
x=(xi) of X and let K be the finite subset of I such that
Ui=Xi if and only if
i∈K. Let
Vi be
Xi for
i∈/J∪K, and let
Vi be a connected neighbourhood of
xi contained in
Ui for
i∈J∪K; then
V=i∈I∏Vi is connected (by Proposition 8 of no. 4) and is a neighbourhood of
x contained in U. Hence X is locally connected.
b) Let a=(ai) be a point of X and let V be a connected neighbourhood of a in X. Since we have priV=Xi except for a finite number of indices (§ 4, no. 1) it follows from no. 2, Proposition 4 that the Xi are connected, for all but a finite number of indices. On the other hand, for each x∈I, each ax∈Xx and each neighbourhood Vx of ax in Xx, there is a point x of X such that prxx=ax, and
V=Vx×i=x∏Xi is a neighbourhood of
x in X; V therefore contains a connected neighbourhood W of
x, whose projection
prxW is a connected neighbourhood of
ax contained in
Vx (no. 2, Proposition 4 and § 4, no. 2, Proposition 5). Hence each
Xx is locally connected.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.