Proposition 11
Tag 0CDZ, permanent. Cite it as [Bourbaki, Tag 0CDZ].
General Topology, chapter X, § 3. Special function spaces
Let be a compact space and let be the group of all homeomorphisms of onto itself. Then the topology of uniform convergence in is compatible with the group structure of .
We know already (no. 4, Proposition 9) that the mapping of into is continuous with respect to this topology; thus we have to show that is continuous at every point of . Since is uniformly continuous on , given any symmetric entourage of there exists an entourage of such that the relation implies . Hence, if is such that for all , it follows that for all , and therefore (as is bijective) for all . This completes the proof.
Now let be a locally compact space and let be the group of all homeomorphisms of onto itself. The topology of compact convergence in is not necessarily compatible with the group structure of (Exercise 17). Let denote the compact space obtained by adjoining a point at infinity to . Every homeomorphism of onto itself extends uniquely to a homeomorphism of onto itself such that (Chapter I, § 10, no. 3, Corollary to Proposition 7), so that can be identified with the subgroup of the group of all homeomorphisms of onto itself, consisting of all homeomorphisms which leave fixed. The topology induced on by that of is therefore compatible with the group structure of (Proposition 11), and is closed in [with respect to the topology induced by that of ] because it is defined by the equation (§ 1, no. 2, Remark 6). We denote by the group topology thus defined on ; it is finer than the topology of compact convergence and can also (by virtue of § 1, no. 6, Proposition 6) be defined as the topology of uniform convergence on , when is endowed with the uniformity induced by the unique uniformity of .
The topology can be characterized as follows:
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.