Bourbaki

习题 2, § 6

标签 0C9L,永久不变。引用为 [Bourbaki, Tag 0C9L]。

一般拓扑, IX

Bourbaki marks this one as harder than the rest.

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a) 令 XX 为可度量的空间。证明以下性质是等价的:

α)\alpha) There exists a metric dd compatible with 拓扑 of XX, with respect to which XX is an ultrametric 空间 (§2§ 2, 习题 4).

β)\beta) XX 是强零维的。

γ)\gamma) There exists 序列 (Bn)(\mathscr{B}_n) of locally finite families of open and closed 子集 of XX such that B=⋃nBn\mathscr{B} = \bigcup_n \mathscr{B}_n is 基 for 拓扑 of XX.

[To show that α)\alpha) implies β)\beta), 注 that if FF is a closed 集合 in an ultrametric 空间 XX, then 集合 of all x∈Xx \in X such that d(x,F)=ρ>0d(x, F) = \rho > 0 is both open and closed in XX。要证明β)\beta)蕴含γ)\gamma),请使用§4§ 4的引理 3、no. 5和§6§ 6的习题 1 c)。 Finally, to establish that γ)\gamma) implies α)\alpha), 约化 to the case where Bn=(Un,λ)λ∈L\mathscr{B}_n = (U_{n, \lambda})_{\lambda \in L}, and if fn,λf_{n, \lambda} is the characteristic 函数 of Un,λU_{n, \lambda}, consider 映射 x↦f(x)=fn,λ(x)x \mapsto f(x) = f_{n, \lambda}(x) of XX into 乘积群 GN×LG^{N \times L},其中 G=Z/2ZG = \mathbf{Z}/2\mathbf{Z}(与集合 {0,1}\{0, 1\} 标识); for each n∈Nn \in \mathbf{N}, let GnG_n be 子群 of GG 由……组成 of 元素 whose (k,λ)(k, \lambda) coordinates are 零 for all λ∈L\lambda \in L and all k<nk < n; show that if GG is endowed with 群拓扑 for which (Gn)(G_n) is a fundamental 系统 of 邻域 of 0, then ff is a homeomorphism of XX onto 子空间 of GG; and complete 证明 by noting that 拓扑 of GG can be defined by an invariant metric with respect to which GG is an ultrametric 空间.]

b) Deduce from a) that every zero-dimensional Hausdorff 空间 XX which has a countable 基 is a strongly zero-dimensional metrizable 空间. (Show by using §2§ 2, no. 8, 命题 13 that there exists a countable 基 formed of 集合 which are both open and closed.) Furthermore, XX is then homeomorphic to 子空间 of Cantor's triadic 集合 KK(cf.§2§ 2,习题12(*)。)

(*) 尚不清楚是否每个零维可度量空间都是强零维的。

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Google 翻译生成的粗略草稿,质量较低。术语依照术语表,但句子可能有误;之后会由仔细的译文取代。