Bourbaki

Proposition 8

Tag 0061, permanent. Cite it as [Bourbaki, Tag 0061].

Algebra, VIII, p. 87, § 5. Commutation

a) The mapping z↦(zSλ)λ∈SMz\mapsto (z_{S_{\lambda}})_{\lambda\in\mathscr{S}_M} is an isomorphism from Z to the product of the fields ZλZ_{\lambda}.

b) The A-module M is isotypical and nonzero if and only if Z is a field.

c) Let Λ be a subset of SM\mathscr{S}_M. Denote by eΛe_{\Lambda} the unique element of Z such that (eΛ)Sλ=1Sλ(e_{\Lambda})_{S_{\lambda}}= 1_{S_{\lambda}} for λ∈Λ\lambda \in \Lambda and (eΛ)Sλ=0(e_{\Lambda})_{S_{\lambda}}= 0 for λ∈SM−Λ\lambda \in \mathscr{S}_M-\Lambda. We have (eΛ)Mλ=1Mλ(e_{\Lambda})_{M_{\lambda}}= 1_{M_{\lambda}} for λ∈Λ\lambda \in \Lambda and (eΛ)Mλ=0(e_{\Lambda})_{M_{\lambda}}= 0 for λ∈SM−Λ\lambda \in \mathscr{S}_M-\Lambda.

d) If the support SM\mathscr{S}_M of M is finite, then the mapping Λ↦eΛZ\Lambda \mapsto e_{\Lambda}Z is a bijection from the set of subsets of SM\mathscr{S}_M to the set of ideals of Z, and the mapping a↦aM\mathfrak{a}\mapsto \mathfrak{a}M is a bijection from the set of ideals of Z to the set of (A,Bo)(A,B^o)-sub-bimodules of M. These bijections are isomorphisms of ordered sets. The reverse bijection sends an (A,Bo)(A,B^o)-sub-bimodule N of M to the ideal consisting of the elements zz of Z that send N into M.

For λ∈SM,Zλ\lambda \in \mathscr{S}_M, Z_{\lambda} is the common center of the commutant DλD_{\lambda} and the bicommutant CλC_{\lambda} of the A-module SλS_{\lambda}. By Proposition 7, c) above, the mapping c↦(cλ)λ∈SMc\mapsto (c_{\lambda})_{\lambda\in\mathscr{S}_M} is an isomorphism from C to ∏λ∈SMCλ\prod_{\lambda\in\mathscr{S}_M}C_{\lambda}. By restriction to the centers, we obtain the isomorphism z↦(zSλ)λ∈SMz\mapsto (z_{S_{\lambda}})_{\lambda\in\mathscr{S}_M} from Z to ∏λ∈SMZλ\prod_{\lambda\in\mathscr{S}_M}Z_{\lambda}, whence a).

The ring ∏λ∈SMZλ\prod_{\lambda\in\mathscr{S}_M}Z_{\lambda} is a field if and only if the set SM\mathscr{S}_M has a single element, whence b).

Assertion c) follows from Proposition 7, a). Suppose that SM\mathscr{S}_M is finite. It follows from a) and Proposition 8 of I, §8, No. 10, p. 109, that the mapping Λ↦eΛZ\Lambda \mapsto e_{\Lambda}Z is an isomorphism of ordered sets from P(SM)\mathfrak{P}(\mathscr{S}_M) to the set of ideals of Z. Let Λ be a subset of SM\mathscr{S}_M. By c), we have the relation eΛe_{\Lambda}ZM =eΛM==e_{\Lambda}M = ⨁λ∈ΛMλ\bigoplus_{\lambda\in\Lambda}M_{\lambda}; because of Proposition 6, c) of VIII, p. 86, it remains to describe the inverse bijection. But z∈Zz\in Z sends M into ⨁λ∈ΛMλ\bigoplus_{\lambda\in\Lambda}M_{\lambda} if and only if z=eΛzz=e_{\Lambda}z, that is, z∈eΛZz\in e_{\Lambda}Z.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2023, Springer Nature. Not translated.