Bourbaki

Proposition 16

Tag 05T2, permanent. Cite it as [Bourbaki, Tag 05T2].

Algebra, chapter II, § 7. Vector spaces

(i) Let K, L be two fields, E a left vector space over K, F a left vector space over L and G a (K, L)-bimodule. Then the canonical Z\mathbf{Z}-homomorphism

ν:Hom⁡K(E,G)⊗LF→Hom⁡K(E,G⊗LF) \nu : \operatorname{Hom}_K(E, G) \otimes_L F \to \operatorname{Hom}_K(E, G \otimes_L F)

(§ 4, no. 2, formula (7)) is injective; it is bijective when one of the vector spaces E, F is finite-dimensional.

(ii) Let E1,E2,F1,F2E_1, E_2, F_1, F_2 be four vector spaces over a commutative field K; then the canonical K-homomorphism

λ:Hom⁡(E1,F1)⊗Hom⁡(E2,F2)→Hom⁡(E1⊗E2,F1⊗F2) \lambda : \operatorname{Hom}(E_1, F_1) \otimes \operatorname{Hom}(E_2, F_2) \to \operatorname{Hom}(E_1 \otimes E_2, F_1 \otimes F_2)

(§ 4, no. 4, formula (21)) is injective; it is bijective if one of the ordered pairs (E1,E2),(E1,F1),(E2,F2)(E_1, E_2), (E_1, F_1), (E_2, F_2) consists of finite-dimensional spaces.

Assertion (i) is a particular case of § 4, no. 2, Proposition 2. Similarly the second assertion of (ii) is a particular case of § 4, no. 4, Proposition 4. Finally, to see that the homomorphism (28) is always injective, observe that Hom⁡(Ei,Fi)\operatorname{Hom}(E_i, F_i) is a vector subspace of FiEiF_i^{E_i} (i=1,2i = 1, 2) and that

Hom⁡(E1⊗E2,F1⊗F2) \operatorname{Hom}(E_1 \otimes E_2, F_1 \otimes F_2)

is canonically identified with a vector subspace of the space (F1⊗F2)E1×E2(F_1 \otimes F_2)^{E_1 \times E_2} (II, § 3, no. 1, Proposition 1); when these identifications are made and also the left hand side of (28) is identified with a subspace of F1E1⊗F2E2F_1^{E_1} \otimes F_2^{E_2} (Proposition 14), the canonical mapping (28) becomes the restriction to this subspace of the canonical mapping (26) and it has been seen (Proposition 15) that the latter is injective.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Cites

Transcribed from the printed edition, 1998, Springer. Not translated.