— Suppose that the conditions of Prop. 13 are fulfilled and that, in addition, Y is normal.
a) The restriction of μG to Ω is, up to a constant factor, the image of μX⊗μY under the mapping (x,y)↦xy of X×Y onto Ω.
b) For x∈X and y∈Y,
ΔG(xy)=ΔX(x)ΔY(y)mod(ix),
where ix denotes the automorphism v↦x−1vx of Y.
We have ΔG=ΔY on Y (Prop. 10 b)), therefore a) follows from (23). Let x0∈X, y0∈Y. Denote by p the mapping (x,y)↦xy of X×Y onto Ω. Since
xy(x0y0)−1=xx0−1(x0yy0−1x0−1)=xx0−1ix0−1(yy0−1),
we have
ΔG(x0y0)p(μX⊗μY)=δ(x0y0)p(μX⊗μY)=p(δ(x0)μX⊗ix0−1δ(y0)μY)=p(ΔX(x0)μX⊗ΔY(y0)(mod ix0)μY)=ΔX(x0)ΔY(y0)(mod ix0)p(μX⊗μY),
whence b).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.