— Let Γ0 be the set of measures α∈Γ such that Hα is unimodular, and for every α∈Γ0 set μα=μ/α; then the mapping α↦∥μα∥ of Γ0 into R is lower semi-continuous for the vague topology.
For every α∈Γ0 and every function f∈K(G), set
fα(x˙)=∫Hαf(xs)dα(s)=(f∗α)(x),
where the convolution product is taken relative to the right Haar measure μ and where one makes use of the fact that α˙=α (§ 4, No. 4, formula (11)). We know (Ch. VII, §2, No. 1, Prop. 2) that the mapping f↦fα of K+(G) into K+(Qα) is surjective; therefore, by (2),
∥μα∥=f∈K+(G),f=0supμα(fα)/∥fα∥=f∈K+(G),f=0supμ(f)/∥fα∥,
where one has set
∥fα∥=x˙∈Qαsup∣fα(x˙)∣=x∈Gsup∣(f∗α)(x)∣.
To establish the proposition, it will suffice to show that, given f∈H+(G), the mapping α↦∥fα∥ is vaguely continuous. Now, let K be the support of f; the function f∗α has its support contained in KHα and is invariant on the right under Hα; consequently
∥fα∥=x∈Ksup∣(f∗α)(x)∣.
The conclusion therefore follows from the fact that the mapping α↦f∗α of M+(G) equipped with the vague topology, into C(G) equipped with the topology of compact convergence, is continuous (§ 4, No. 2, Remark 1).
Recall that if, for a measure α∈Γ0, ∥μα∥ is finite, then G is necessarily unimodular (Ch. VII, §2, No. 6, Cor. 3 of Th. 3).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.