Bourbaki

Proposition 9

Tag 0B1M, permanent. Cite it as [Bourbaki, Tag 0B1M].

General Topology, chapter I, § 3. Subspaces, quotient spaces

Let f:X→Yf : X \to Y be a continuous surjection, and let RR denote the equivalence relation f(x)=f(y)f(x) = f(y). If there is a continuous section s:Y→Xs : Y \to X associated with ff (Set Theory, Chapter II, § 3, no. 8, Definition 11), then the mapping g:X/R→Yg : X/R \to Y associated with ff is a homeomorphism, and ss is a homeomorphism of YY onto the subspace s(Y)s(Y) of XX.

For if φ:X→X/R\varphi : X \to X/R is the canonical mapping, then gg and φ∘s\varphi \circ s are bijective, continuous and inverse to each other; likewise ss and the restriction of ff to s(Y)s(Y) are bijective, continuous and inverse to each other.

If RR is an equivalence relation on a topological space XX and

φ:X→X/R \varphi : X \to X/R
is the canonical mapping, a continuous section s:X/R→Xs : X/R \to X associated with φ\varphi is also called a continuous section of XX with respect to RR (cf. Set Theory, Chapter II, § 6, no. 2); the subspace s(X/R)s(X/R) of XX is then homeomorphic to X/RX/R. If we are given s(X/R)s(X/R), then ss is uniquely determined; s(X/R)s(X/R) is often called, by abuse of language, a (continuous) section of XX with respect to RR.

A continuous section of a topological space with respect to an equivalence relation need not exist (Exercise 12).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed volume. Not translated.