Bourbaki

Corollary 1

Tag 0C43, permanent. Cite it as [Bourbaki, Tag 0C43].

General Topology, chapter IX, § 3. Metrizable groups, valued fields, normed spaces and algebras

Let G be a complete metrizable group, let G0 be a dense subgroup of G and let H_0 be a closed normal subgroup of G_0. If H is the closure of H_0 in G, the quotient group G_0/H_0 has a completion isomorphic to G/H.*

H is a normal subgroup of G (Chapter III, § 2, no. 3, Proposition 8) and Proposition 4 shows that G/H is complete. Also if φ\varphi is the canonical mapping of G onto G/H, it is clear that φ(G0)\varphi(G_0) is dense in G/H. The result therefore follows from Chapter III, § 2, no. 7, Proposition 21.

Let G, G' be two Hausdorff abelian topological groups, and G^,G^′\hat{G}, \hat{G}' their respective completions. We recall (Chapter III, § 3, no. 3, Proposition 5) that if uu is a continuous homomorphism of G into G', then uu is uniformly continuous and extends uniquely to a continuous homomorphism of G^\hat{G} into G^′\hat{G}', which we shall denote by u^\hat{u} in the remainder

(*) There exist non-metrizable complete groups G containing a closed subgroup H such that G/H is not complete.

of this subsection. The diagram

G→uG′i↓i′↓G^→u^G^′ \begin{array}{ccc} G & \xrightarrow{u} & G' \\ i \downarrow & & i' \downarrow \\ \hat{G} & \xrightarrow{\hat{u}} & \hat{G}' \end{array}

in which i,i′i, i' are the canonical injections) is commutative. If vv is a continuous homomorphism of G′G' into a Hausdorff abelian topological group G′′G'', and if w=v∘uw = v \circ u, then it is follows immediately that w^=v^∘u^\hat{w} = \hat{v} \circ \hat{u}.

Let HH be a closed subgroup of GG and let E=G/HE = G/H. Let j:H→Gj : H \to G and p:G→Ep : G \to E be the canonical mappings. Let H‾\overline{H} be the closure of HH in G^\hat{G}; H‾\overline{H} is a complete group and we identify it with the completion H^\hat{H} of HH. The continuous extension j^\hat{j} of jj to H^\hat{H} is evidently the canonical injection of H^\hat{H} in G^\hat{G}.

Suppose from now on that GG is metrizable. Then the canonical mapping of E=GHE = GH into G^H^\hat{G}\hat{H} is a topological isomorphism of EE onto a dense subgroup of the complete group G^/H^\hat{G}/\hat{H} (Corollary 1), and thus we may identify G^H^\hat{G}\hat{H} with E^\hat{E} and the continuous extension p^\hat{p} of pp to G^\hat{G} with the canonical mapping of G^\hat{G} onto G^/H^\hat{G}/\hat{H}.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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