Bourbaki

习题 4, § 5

标签 04J2,永久不变。引用为 [Bourbaki, Tag 04J2]。

交换代数, III, 259

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令AA为交换环,33为AA和S=1+3S = 1 + 3的理想。 Show that, if MM is an absolutely Hausdorff AA-module with respect to g\mathfrak{g}, then S−1M=MS^{-1}M = M, in other words, for all a∈Sa \in S, x↦axx \mapsto ax is a bijection of MM onto itself. (Show first that the hypothesis that MM is Hausdorff with the 33-adic topology implies that x↦axx \mapsto ax is injective; then prove that the submodule aMaM of MM is dense in MM with the 88-adic topology and use Exercise 1 (a).)

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Google 翻译生成的粗略草稿,质量较低。术语依照术语表,但句子可能有误;之后会由仔细的译文取代。