Bourbaki

Proposition 8

Tag 092X, permanent. Cite it as [Bourbaki, Tag 092X].

Integration, V, p. 47, § 5. Measures defined by numerical densities

Let θ\theta be a complex measure on TT, g1g_1 a locally θ\theta-integrable complex function, θ1\theta_1 the measure g1⋅θg_1 \cdot \theta. For a complex function g2g_2 defined on TT to be locally θ1\theta_1-integrable, it is necessary and sufficient that g2g1g_2 g_1 be locally θ\theta-integrable, in which case

g2⋅θ1=g2⋅(g1⋅θ)=(g2g1)⋅θ g_2 \cdot \theta_1 = g_2 \cdot (g_1 \cdot \theta) = (g_2 g_1) \cdot \theta
('associativity formula').

By the corollary of Prop. 4, to say that g2g_2 is θ1\theta_1-measurable is equivalent to saying that g2g1g_2 g_1 is θ\theta-measurable. Let us suppose this condition to be satisfied. For every function f∈K+(T)f \in \mathscr{K}_+(T) we have, by Propositions 2 and 3,

∫∙∣g2∣fd∣θ1∣=∫∙∣g2∣f∣g1∣d∣θ∣=∫∙∣g2g1∣fd∣θ∣. \int^\bullet |g_2| f d|\theta_1| = \int^\bullet |g_2| f |g_1| d|\theta| = \int^\bullet |g_2 g_1| f d|\theta|.

To say that g2g_2 is locally θ1\theta_1-integrable is therefore equivalent to saying that g2g1g_2 g_1 is locally θ\theta-integrable. Assuming this condition to be satisfied, by Th. 1 we have

∫f d(g2⋅θ1)=∫fg2 dθ1=∫fg2g1 dθ=∫f d(g2g1⋅θ), \int f \, d(g_2 \cdot \theta_1) = \int f g_2 \, d\theta_1 = \int f g_2 g_1 \, d\theta = \int f \, d(g_2 g_1 \cdot \theta),

a formula equivalent to (10).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.