*Let X be a locally compact space countable at infinity, H a discrete group operating continuously and properly on the right in X, π the canonical mapping of X onto X/H, μ a positive measure on X invariant under H, β the normalized Haar measure of H, and λ = μ/β. Let F be a μ-measurable fundamental domain.
a) The pair (π,n−1φF) is μ-adapted, and
∫Xn(x)−1φF(x)επ(x)dμ(x)=λ.
b) The mapping π is proper for n−1φF⋅μ, and π(n−1φF⋅μ)=λ.
c) Let k be a function on X/H. For k to be λ-measurable (resp. λ-integrable), it is necessary and sufficient that n−1φF(k∘π) be μ-measurable (resp. μ-integrable); and, if k is λ-integrable then
∫X/Hkdλ=∫Fn−1(k∘π)dμ.
We have μ=λ♯. Let f∈H+(X/H). Then n−1φF(f∘π) is μ-measurable and ≥0, and by Prop. 5 b) of No. 3 we have
∫X∗n(x)−1φF(x)f(π(x))dμ(x)=∫X/H∗f(x˙)dλ(x˙)∫H∗n(xξ)−1φF(xξ)dβ(ξ)
and ∫H∗n(xξ)−1φF(xξ)dβ(ξ)=n(x)−1∑ξ∈HφF(xξ)=1 by Lemma 8. Thus n−1φF⋅(f∘π) is μ-integrable and
∫Xn(x)−1φF(x)f(π(x))dμ(x)=∫X/Hf(x˙)dλ(x˙).
This proves a). The assertion b) is proved similarly. The assertion c) may be deduced from a) and from Ch. V, §4, Prop. 3 and Th. 2.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.