Bourbaki

Theorem 1

Tag 0BLE, permanent. Cite it as [Bourbaki, Tag 0BLE].

General Topology, chapter III, § 4. Groups operating properly on a topological space; compact ness in topological groups and spaces with operators

Let GG be a Hausdorff topological group which operates continuously on a topological space XX. Let KK be a compact subset of XX and let LL be a closed subset of XX. Then: a) The set P(K,L)P(K, L) is closed in GG.

b) If G operates properly on X and if L is compact, then P(K, L) is compact.

c) Conversely, if X is locally compact and if, for each pair K, L of compact subsets of X, P(K, L) is relatively compact in G [and therefore compact by a)]; then G operates properly on X (and if X is not empty, G is locally compact by Proposition 11).

The mapping (s,x)→s.x(s, x) \to s.x of G×KG \times K into XX is continuous, and the inverse image L′L' of LL under this mapping is therefore closed. Since KK is compact, the projection pr⁡1:G×K→G\operatorname{pr}_1 : G \times K \to G is proper (Chapter I, § 10, no. 2, Corollary 5 of Theorem 1) and the image of L′L' under pr⁡1\operatorname{pr}_1 is therefore closed. This image is P(K,L)P(K, L), hence a) is proved.

To prove b): XX is Hausdorff (no. 2, Proposition 3). By hypothesis the mapping θ:(s,x)→(x,s.x)\theta : (s, x) \to (x, s.x) of G×XG \times X into X×XX \times X is proper; since K×LK \times L is compact, so is θ‾(K×L)\overline{\theta}(K \times L) since XX is Hausdorff (Chapter I, § 10, no. 2, Proposition 6). Hence the projection P(K,L)P(K, L) of θ‾(K×L)\overline{\theta}(K \times L) into GG is a compact set.

To prove c): since K×LK \times L is closed in X×XX \times X, it follows that θ‾(K×L)\overline{\theta}(K \times L) is closed in P(K,L)×KP(K, L) \times K and is therefore compact under the hypotheses of c). Since every compact subset of X×XX \times X is contained in a compact subset of the form K×LK \times L, it follows that the inverse image of any compact subset of X×XX \times X under θ\theta is compact, and since X×XX \times X is locally compact, this shows that θ\theta is proper (Chapter I, § 10, no. 3, Proposition 7) [see Chapter IV, § 1, Exercise 4c)].

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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