Bourbaki

Theorem 3

Tag 04GL, permanent. Cite it as [Bourbaki, Tag 04GL].

Commutative Algebra, chapter III, § 3. m-adic topologies on Noetherian rings

Let A be a commutative Noetherian ring, m an ideal of A and E, F, G threefinitely generated A-modules. Then:

(i) If E→uF→vGE \xrightarrow{u} F \xrightarrow{v} G is an exact sequence of A-linear mappings, the sequence E^→u^F^→v^G^\hat{E} \xrightarrow{\hat{u}} \hat{F} \xrightarrow{\hat{v}} \hat{G} obtained by passing to the Hausdorff completions (with respect to the m-adic topologies) is exact.

(ii) The canonical A-linear mapping αE:A^⊗AE→E^\alpha_E : \hat{A} \otimes_A E \to \hat{E} is bijective.

(iii) The A-module A^\hat{A} is flat.

We have seen that uu and vv are strict morphisms of topological groups (no. 2, Corollary to Theorem 2). Assertion (i) then follows from § 2, no. 12, Lemma 2. Assertion (ii) is obvious when E=AE = A and the case where E is a free finitely generated A-module can be immediately reduced to that. In the general case, E admits a finite presentation

L→uL′→vE⟶0 L \xrightarrow{u} L' \xrightarrow{v} E \longrightarrow 0

(Chapter I, § 2, no. 8, Lemma 8). We derive a commutative diagram

A^⊗AL→1⊗uA^⊗AL′→1⊗vA^⊗AE⟶0↓αL↓αL′↓αEL^⟶L^′⟶E^⟶ \begin{array}{ccccccccc} \hat{A} \otimes_A L & \xrightarrow{1 \otimes u} & \hat{A} \otimes_A L' & \xrightarrow{1 \otimes v} & \hat{A} \otimes_A E & \longrightarrow & 0 \\ \downarrow \alpha_L & & \downarrow \alpha_{L'} & & \downarrow \alpha_E \\ \hat{L} & \longrightarrow & \hat{L}' & \longrightarrow & \hat{E} & \longrightarrow & \end{array}

The first row is exact (Chapter I, § 2, no. 1, Lemma 1) and so is the second by (i). We already know that αE\alpha_E is surjective (§ 2, no. 12, Proposition 16); on the other hand, as αL\alpha_L and αL′\alpha_{L'} are bijective and 1⊗v1 \otimes v is surjective, αE\alpha_E is injective by virtue of Chapter I, § 1, no. 4, Corollary 2 to Proposition 2; this shows (ii).

Then it follows from (i) and (ii) that, if aa is an ideal of A (necessarily finitely generated), the canonical mapping A^⊗Aa→A^\hat{A} \otimes_A a \to \hat{A} is injective, being the composition of a^→A^\hat{a} \to \hat{A} and αE\alpha_E, which proves that A^\hat{A} is a flat AA-module (Chapter I, § 2, no. 3, Proposition 1).

Under the conditions of Theorem 3 A^⊗AE\hat{A} \otimes_A E is often identified with EE by means of the canonical mapping αE\alpha_E. If u:E→Fu : E \to F is a homomorphism of finitely generated AA-modules, u^:E→F^\hat{u} : E \to \hat{F} is then identified with 1@u1 @ u by virtue of the commutativity of diagram (4).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Cites

Transcribed from the printed volume. Not translated.