§ 7. Irreducible representations of connected compact Lie groups
We retain the notations of §6. A representation of G is a continuous (hence analytic) homomorphism from G to a group , where V is a finite dimensional complex vector space. Every representation of G is semi-simple (§1, no. 1).
Choose a chamber C of §5, no. 2), and put .
1. Dominant characters
Denote by the set of elements of X(T) such that for all , that is, such that the linear form maps the chamber C of to .
Give X(T) the ordered group structure for which the positive elements are those of ; put and . The elements of are called positive roots, those of negative roots; every root is either positive or negative (Chap. VI, §1, no. 6, Th. 3). A positive root that is not the sum of two positive roots is said to be simple; every positive root is a sum of simple roots (loc. cit.); the simple roots form a basis of the subgroup of X(T) generated by the roots, a subgroup that can be identified with (§4, no. 4); the reflections with respect to the simple roots generate the Weyl group (Chap. VI, §1, no. 5, Th. 2).
Lemma 1 01FZ
Let be an element of X(T). The following conditions are equivalent:
(i) (resp. ) for all such that ;
(ii) for all such that is a linear combination with positive coefficients (resp. positive coefficients not all zero) of simple roots;
(iii) (resp. ) for every positive root ;
(iv) (resp. ) for every simple root .
The equivalence if (iii) and (iv) is immediate. Since the set of the can be identified with the inverse root system of §4, no. 5), the equivalence of (i) and (iii) follows from Chap. VI, §1, no. 6, Prop. 18 and Cor. The implication (ii) (i) is trivial, and the opposite implication follows from loc. cit.
Denote by the set of elements of X(T) such that for every positive root . The elements of are said to be dominant. They form a fundamental domain for the operation of W on X(T) (Chap. VI, §1, no. 10). We have .
If G is simply-connected, for each simple root there exists an element of X(T) such that for every simple root , that is, for every simple root ; the are called the fundamental dominant weights; they form a basis of the commutative group X(T) and of the commutative monoid ; more precisely, every element of X(T) can be written in the form .
Denote by the element of such that
We have for every simple root (Chap. VI, §1, no. 10, Prop. 29). If G is simply-connected, is the sum of the fundamental dominant weights.
2. Highest weight of an irreducible representation
Associate to any representation the homomorphism from the -Lie algebra to End(V) extending the linear representation of on the real vector space underlying V (Chap. III, §3, no. 11). By Prop. 7 of §4, no. 3, the map from X(T) to Hom induces a bijection from the set of weights of relative to T to the set of weights of relative to the Cartan subalgebra of .
Lemma 2 01G0
Let be a linear representation of the complex Lie algebra on a finite dimensional complex vector space V. There exists a representation of G on V such that if and only if is semi-simple and the weights of on V belong to .
If there exists a representation of G such that , then is semi-simple because G is connected and is semi-simple (Chap. III, §6, no. 5, Cor. 2 of Prop. 13), and the weights of on V belong to the image of . Thus, the condition is necessary; we shall prove that it is sufficient. If is semi-simple, V is the direct sum of the , where belongs to the set of weights of on V (Chap. VII, §2, no. 4, Cor. 3 of Th. 2); if all the weights belong to the image of , there exists a representation of T on V such that indeed, it suffices to put for and . The lemma now follows from Prop. 8 of §2, no. 6.
Theorem 1 01G1
a) Let be an irreducible representation of G. Then the set of weights of (relative to T) has a largest element , which is dominant, and the space is of dimension 1.
b) Two irreducible representations of G are equivalent if and only if their highest weights are equal.
c) For every dominant element of X(T), there exists an irreducible representation of G of highest weight .
By Lemma 2, the equivalence classes of irreducible representations of G correspond bijectively to the classes of finite dimensional irreducible representations of whose weights belong to .
Denote by the centre and by the derived Lie algebra of , so that . For every bilinear form on , denote by the simple -module introduced in Chap. VIII, §6, no. 3; for every linear form on , denote by the 1-dimensional -module over associated to it. Then the -modules are simple, and by Chap. VIII, §7, no. 2, Cor. 2 of Th. 1 and Algebra, Chap. VIII, §11, no. 1, Th. 1, every finite dimensional simple -module is isomorphic to one of the modules ; moreover (loc. cit.) is finite dimensional if and only if is a positive integer for every simple root . If we denote by the linear form on that induces on and on , then ; moreover, the weights of are the , where is any weight of , and are thus of the form , with (Chap. VIII, §6, no. 2, Lemma 2).
We conclude that the -module is finite dimensional if and only if is a positive integer for every simple root , and that its weights belong to if and only if belongs to . The conjunction of these two conditions means that belongs to ; in that case, is the highest weight of . Thus, we have constructed for every dominant weight of X(T) an irreducible representation of G of highest weight , and have thus obtained, up to equivalence, all the irreducible representations of G. Since the vectors of weight in form a subspace of dimension 1, the proof is complete.
Corollary 01G2
The group G has a (finite dimensional) faithful linear representation.
Observe first that every element of X(T) is equal to the difference of two dominant weights: more precisely, let be an element of such that for every simple root ; for all there exists a positive integer such that for every simple root , that is (no. 1, Lemma ).
Consequently, there exists a finite family of elements of generating the -module X(T). For , let be an irreducible representation of G of highest weight (Th. 1); let the representation be the direct sum of the . By construction the set of weights of (relative to T) generates the -module X(T). It now follows from Prop. 6 of §4, no. 3 that the homomorphism is injective, hence the corollary.
Remark 1 01G3
Let be the subalgebra of that is the sum of the for . Let be an irreducible representation, its highest weight and the representation induced by . Then is the subspace consisting of the vectors in V such that for all .
Indeed, this follows from the corresponding statement for the -modules (Chap. VIII, §6, no. 2, Prop. 3).
Remark 2 01G4
Let be the algebra of continuous representative functions on G with values in Algebra, Chap. VIII). Let G operate on by left and right translations. For each , let be an irreducible representation of G of highest weight (Th. 1), and the contragredient representation (Chap. III, §3, no. 11); by Spectral Theories, the representation of on is isomorphic to the direct sum of the representations for all in . Remark 1 now implies the following statement: Let , and let be the vector subspace of consisting of the continuous representative functions on G such that for all and all , and such that for all .
Then is stable under left translations, and the representation of G on by left translations is irreducible of highest weight .
Remark 3 01G5
Let be an irreducible representation. There exists an element of X(C(G)) such that for all indeed, is contained in the commutant of (G), which is equal to Algebra, Chap. VIII, §3, no. 2, Th. 1). For every weight of , the restriction of to C(G) is equal to .
Remark 4 01G6
The definitions and statements of Chap. VIII, §7, nos. 2 to 5 can be generalized without difficulty to the present situation; we leave the details to the reader.
Proposition 1 01G7
Let be an irreducible representation of G of highest weight . Let be the integer , and let
be the element of the Weyl group such that (Chap. VI, § 6, Cor. 3 of Prop. 17). There are three possible cases:
a and is even. Then there exists a G-invariant separating symmetric bilinear form on V; the representation is of real type (Appendix II).
b. Every G-invariant bilinear form on V is zero; the representation is of complex type (loc. cit.).
c and is odd. Then there exists a G-invariant separating alternating bilinear form on V; the representation is of quaternionic type (loc. cit.).
If the restriction of to is not trivial, we are in case b).
A bilinear form B on V is invariant under G if and only if it is invariant under (Chap. III, §6, no. 5, Cor. 3). Thus, if G is semi-simple, the proposition follows from Chap. VIII, §7, no. 5, Prop. 12 and Prop. 3 of Appendix II.
In the general case, put , and identify with a subgroup of X(T) (stable under W). If induces by passage to the quotient a representation of highest weight ; in this case the proposition follows from the preceding, applied to .
Assume that . There exists a non-zero element of X(S) such that for all (Remark 3). Then is the image of under the restriction homomorphism ; since W operates trivially on X(S), the equality implies that , which is impossible: hence . On the other hand, if B is a G-invariant bilinear form on V, we have, for all in V and in S,
which implies that B = 0, hence the proposition.
Let be the set of classes of irreducible continuous representations of G on finite dimensional real vector spaces. Prop. 1 and the results of Appendix II give a bijection (G), where denotes the subgroup of Aut(X(T)). More precisely, let , and let be a representation of G of highest weight ; then
if or if
if and
where is an -structure on invariant under G.
3. The ring r(g)
Let R(G) be the ring of representations (continuous, on finite dimensional complex vector spaces) of G (Algebra, Chap. VIII, §10, no. 6). If is a representation of G, denote by its class in R(G); if and are two representations of G, we have, by definition,
Since every representation of G is semi-simple, the -module R(G) is free and admits as a basis the set of classes of irreducible representations of G, a set that can be identified with by Th. 1. The map induces a homomorphism from the ring R(G) to the ring of representations of (Chap. VIII, §7, no. 6).
Let be a representation of G; we consider the gradation of the -vector space V. Denote by Ch(V), or by Ch( ), the character of the graded vector space V (Chap. VIII, §7, no. 7); if denotes the canonical basis of the algebra , we have, by definition,
Ch( ) (dim ).
We define in the same way (loc. cit.) a homomorphism of rings, also denoted by Ch, from R(G) to . If G is semi-simple, we have a commutative diagram
R(G)
where P denotes the group of weights of and the homomorphism induced by .
The Weyl group W operates by automorphisms on the group X(T), and hence on the ring . By Prop. 5 of §4, no. 3, the image of Ch is contained in the subring consisting of the elements invariant under W.
Proposition 2 01G8
The homomorphism Ch induces an isomorphism from R(G) to .
For , denote by the class in R(G) of the irreducible representation of highest weight . Since the family is a basis of the -module R(G), it suffices to prove the following assertion:
The family (Ch[) is a basis of the -module .
For every element of , a term in is called maximal if is a maximal element of the set of such that . Th. 1 implies that Ch[ has a unique maximal term, namely . Thus, the proposition follows from the following lemma.
Lemma 3 01G9
For each , let be an element of having unique maximal term . Then the family is a basis of .
The proof is identical to that of Prop. 3 of Chap. VI, §3, no. 4, replacing A by by X(T) and by .
Let (resp. ) be the -algebra of continuous representative functions on G (resp. T), and let (resp. ) be the subalgebra consisting of the central (resp. W-invariant) functions. The restriction map induces a homomorphism of rings . On the other hand, the map that associates to a representation its character (that is, the function Tr ) extends to a homomorphism of -algebras Tr which, by Spectral Theories, is an isomorphism. Similarly, the canonical injection induces an isomorphism of -algebras (T), which induces an isomorphism . The diagram
is commutative: indeed, for every representation and all ,
Tr (dim )(Ch ),
that is, Tr)[ Ch)[.
We can now deduce from the proposition the following result.
Corollary 01GA
The restriction map is bijective.
4. Character formula
In this number, we write the group X(T) multiplicatively, and regard its elements as complex-valued functions on T. We assume that the element of belongs to X(T).
Denote by the Hilbert space of classes of square-integrable complex functions on T, and by the subspace consisting of the continuous representative functions. By Spectral Theories, X(T) is an orthonormal basis of and an algebraic basis of .
For and , denote by the element of defined by ; thus, for we have . Denote by the signature (the unique homomorphism such that for every reflection ); for (T), put
If , the characters are distinct; indeed, it suffices to prove that for all ; but this follows from Lemma 1 (no. 1) and the fact that for every positive root . Consequently,
Card(W) .
An element is said to be anti-invariant if for all (that is, if for every reflection ). We shall show that is the orthogonal projection of onto the subspace of anti-invariant elements. Indeed, let be in (T), with anti-invariant; then is anti-invariant and
Proposition 3 01GB
The elements , for , form an orthonormal basis of the subspace of anti-invariant elements of , and an algebraic basis of the subspace of anti-invariant elements of .
The proof is identical to that of Chap. VI, §3, no. 3, Prop. 1.
By Chap. VI, loc. cit., Prop. 2,
so
By Cor. 2 of Th. 1 (§6, no. 2), we deduce:
For all , denote by the character of an irreducible representation of G of highest weight .
Theorem 2 (H. Weyl) 01GD
For all , we have .
The function is anti-invariant under W, and is a linear combination with integer coefficients of elements of X(T). Thus, by Chap. VI, §3, no. 3, Prop. 1, it can be written as , where belongs to , and the are integers all but finitely-many of which are zero; since
(Spectral Theories), it follows from Prop. 3 and Lemma 4 that ; thus, the are all zero, except one which must be equal to 1 or . But the coefficient of in is equal to 1 (Th. 1), hence the coefficient of in is equal to 1 (Chap. VI, §3, no. 3, Remark 2), which implies that , hence the theorem.
Corollary 1 01GE
With the notations of no. 3, we have in ,
Ch[ for all .
This follows from the theorem and commutative diagram (2) (no. 3).
Corollary 2 01GF
For all and every regular element of T,
where the two sums are over the elements of W.
Indeed, is non-zero, since is regular (formula (4)).
If is a central function on G, the restriction of to T is invariant under W, so is anti-invariant under W. Further, by Spectral Theories and Th. 1, the family is an algebraic basis of the space of central representative functions on G and an orthonormal basis of the space ZL of classes of square-integrable central functions on G.
Thus, from Prop. 3 and Th. 2 we deduce:
Corollary 3 01GG
The map which associates to any continuous central function on G the function induces an isomorphism from the space of central representative functions on G to the space of anti-invariant elements of ; it extends by continuity to an isomorphism of Hilbert spaces from ZL to the subspace of anti-invariant elements of .
Indeed, by Lemma 4 and Th. 2,
But the function is anti-invariant and is the orthogonal projection of onto the subspace of anti-invariant elements of (T), so
finally, by formula (3), we have , hence the corollary.
Remark 1 01GI
For all , put ; then
If is a regular element of T, we deduce from (5) that
Note that is a linear combination of roots with integer coefficients, and hence belongs to X(T) even if we do not assume that . It follows that formula (7) is valid without the assumption that indeed, to prove this we replace G by a suitable connected covering, and are then reduced to Cor. 2.
Remark 2 01GJ
Similarly, the first equality of Cor. 4 remains valid without the assumption that .
Remark 3 01GK
We can deduce Th. 2 from the analogous infinitesimal statement (Chap. VIII, §9, no. 1, Th. 1); the same is true for Th. 3 of the next number (which is the analogue of Th. 2 of loc. cit., no. 2).
5. Degree of irreducible representations
We now return to the additive notation for the group X(T) and we no longer assume that belongs to X(T).
Theorem 3 01GL
The dimension of the space of an irreducible representation of G of highest weight is given by
Put , so for every simple root (Chap. VI, §1, no. 10, Prop. 29). The line is not contained in any of the hyperplanes Ker , so exp( ) is a regular element of G for all sufficiently small ; for all and all , we have
)(exp( )) .
Let us accept provisionally the following lemma:
Lemma 5 01GM
We have
)(exp( )) .
Thus, the function )(exp( )) is the product of a function that tends to 1 when tends to 0 and of
where N = Card .
Assume first of all that ; applying Cor. 2 of Th. 2 we see that, as tends to tends to
hence the theorem in this case.
In the general case, it suffices to remark that, in proving Th. 3, we can always replace G by a suitable connected covering and thus reduce to the preceding case.
We now prove Lemma 5. Let ; denote by the map from to the -algebra Map(X(T)) of maps from X(T) to that associates to the map
(exp ) .
We have , so there exists a homomorphism of rings
Map(X(T))
such that . On the other hand, by Chap. VI, §3, no. 3, Prop. 2, we have the following relation in
Applying the homomorphism , and using the equality
we deduce the stated formula.
Corollary 1 01GN
Let be a norm on . For all , let be the dimension of the space of an irreducible representation of G of highest weight .
a) sup, where 2(dim dim T).
b) If G is semi-simple, inf.
a) For all , there exists with , hence .
b) Assume that G is semi-simple, denote by the simple roots and put . Then
since , this implies that
sup.
If G is semi-simple, sup is a norm on , necessarily equivalent to the given norm, hence b).
Corollary 2 01GO
Assume that G is semi-simple; let be an integer. The set of classes of representations of G of dimension is finite.
Cor. implies that the set of elements of such that is finite. For all in , let be an irreducible representation of highest weight ; every representation of dimension is isomorphic to a direct sum , with , hence the corollary.
6. Casimir elements
By Prop. 3 of §1, no. 3, there exist negative symmetric bilinear forms on , separating and invariant under Ad(G) (if G is semi-simple, we can take the Killing form of , for example). Let F be such a form. Recall (Chap. I, §3, no. 7) that the Casimir element associated to F is the element of the centre of the enveloping algebra such that, for any basis of satisfying , we have .
In the remainder of this chapter we shall call the Casimir elements of G the elements of obtained in this way from negative separating invariant symmetric bilinear forms on . If is a Casimir element of G and if is an irreducible representation of G, the endomorphism of V is a homothety (Algebra, Chap. VIII, §3, no. 2, Th. 1), whose ratio we shall denote by .
Proposition 4 01GP
Let be the Casimir element of G.
a) If is an irreducible representation of G is real and positive. If is not the trivial representation, .
b) There exists a unique quadratic form on such that, for every irreducible representation of G,
where is the highest weight of . The form is positive, separating and invariant under W.
Let F be a separating negative symmetric bilinear form on defining . Let be an irreducible representation of G; let be a Hilbert scalar product on V invariant under G (§1, no. 1), and a basis of such that . Then, for every element of V not invariant under G we have
hence a).
Let B be the inverse form on of the restriction to of the bilinear form on induced by F by extension of scalars. By the Cor. of Prop. 7 of Chap. VIII, §6, no. 4, we have. Extend to an -linear map from to and let be the quadratic form on ; it is separating and invariant under W, and
We show that the form is positive. Indeed, if , the element of takes purely imaginary values on , hence real values on ; we conclude by remarking that, for , we have .
It remains to prove the uniqueness assertion in b). Let Q be a quadratic form on satisfying the required condition, and let (resp. ) be the bilinear form associated to Q (resp. ). For , we have
Since generates the -vector space , we have , so .
Remark 01GQ
Let . There exists a strictly positive real number A such that, for every irreducible representation and every Hilbert structure on V invariant under G,
Indeed, with the notations in the preceding proof, we can choose the basis of so that . Then, for , we have
Exercises
See the exercises for § 7.